A triangular prism and two nets are shown: A right triangular prism is shown with two nets. The triangular base of the prism has height 5 inches, base 12 inches, and hypotenuse 13 inches. The length of the prism is 15 inches. Net A has 3 rectangles having dimensions 5 by 15, 15 by 12, and 15 by 13, and two triangles having legs 5 inches and 12 inches. Net B has 3 rectangles having dimensions 5 by 13, 13 by 12, and 13 by 15, and two triangles having legs 5 inches and 12 inches.Which is the correct net of the prism and what is the surface area of the prism?A. Net B with 420 square inchesB. Net B with 500 square inchesC. Net A with 510 square inchesD. Net A with 450 square inches
Accepted Solution
A:
Answer:Net for the prism will have 3 rectangles with dimensions 5 by 15, 12 by 15 , and 13 by 15, and 2 triangles with legs 5 inches and 12 inches.
The correct net is net a.
Surface area = sum of areas of the three rectangles and sum of the two triangles.
SA = (5 x 15) + (12 x 15) + (13 x 15) + (5 x 12) = 75 + 180 + 195 + 60 = 510 square inches.Step-by-step explanation:Hope this helped