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Solve for x: 5 β (x + 5) > β2(x + 4)
4 months ago
Q:
Solve for x: 5 β (x + 5) > β2(x + 4)
Accepted Solution
A:
[tex]5 - (x+5) \ \textgreater \ -2(x+4)[/tex]
First we work out the brackets
[tex]5- x -5 \ \textgreater \ -2x - 8 [/tex]
[tex]-x \ \textgreater \ -2x - 8[/tex]
Now we add -2x to both sides of the equation
[tex]x \ \textgreater \ -8[/tex]
Hence, the anser isΒ x > -8